convert: missing an image filename

[Martje]

Hey!

In Python I execute the following code:

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dir = '/home/martijn/Documenten/Eclipse/ponycluboosterwolde/media/afbeeldingen/header/rectangles/'
commands.getstatusoutput('convert -background none %srect_temp.svg %srect_%s.png' % (dir, dir, kleur[1:]))

The following code gets executed on the system:

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convert -background none /home/martijn/Documenten/Eclipse/ponycluboosterwolde/media/afbeeldingen/header/rectangles/rect_temp.svg /home/martijn/Documenten/Eclipse/ponycluboosterwolde/media/afbeeldingen/header/rectangles/rect_39cc00.png

.

/home/mar......./rect_temp.svg exists, the last one (the png) does not. When I run the Python code, ImageMagick reports the following:

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Exit code:256
Message:"convert: missing an image filename `/home/martijn/Documenten/Eclipse/ponycluboosterwolde/media/afbeeldingen/header/rectangles/rect_39cc00.png' @ wand/convert.c/ConvertImageCommand/2710."

However, when I run the code from my terminal, everything goes fine! What's going on?

[fmw42]

you may have to provide the full path to convert in your API call.

[Martje]

Thanks for your suggestion. It doesn't help unfortunately .

[Martje]

It seems some security service is standing in the way . I suspect AppArmor, but it could be SELinux also.

Problem solved!