Legacy ImageMagick Discussions Archive

Hi,

I have a problem, when I call MagickCore::RotateImage with for example -90 degrees, the return image size is not adjusted according to rotation (for example, swap width and height of result image). This results in distortion.... and the method seems to be useless with that feature. How could I call this method to get the image with correct dimensions?

ImageMagick-6.5.0-1

Thanks,

try +distort SRT

see http://www.imagemagick.org/Usage/distorts/#srt

I don't know the API equivalents.

Are you using the call properly. Here's an example:

• rotate_image = RotateImage(image, 90, exception);
  printf("%lu %lu => %lu %lu\n", image->columns, image->rows, rotate_image->columns, rotate_image->rows);

yes, my fault.

RotateImage adjusts image result dimensions.

Their are ways of fixing the rotated image to bring it back to the original size.
See IM examples, Simple Image Warping, Rotating Images
http://www.imagemagick.org/Usage/warping/#rotate

However you may prefer to use the newer Distort Images, which uses a different technique and provides more control of the pixel level distortion that any form of rotation generates
Distorting Images, Scale-Rotate-Translate (SRT) Distortion
http://www.imagemagick.org/Usage/distorts/#srt