Page 1 of 1
Rounded corner border on rounded corner image
Posted: 2010-06-10T11:07:17-07:00
by Bonzo
I am trying to add a red border around an image similar to Anthonys example all in one line:
The two parts work OK but I can not add them together:
Code: Select all
$image = "small.jpg";
$size = getimagesize( $image );
$width = $size[0]+10;
$height = $size[1]+10;
// Creates the red filled rounded rectangle
$cmd = " -size {$width}x{$height} xc:none -fill red -draw \"roundRectangle 5,5 {$width},{$height} 20,20\" -compose dstout -matte ";
// Creates the image with the rounded rectangle
$cmd = " -size {$size[0]}x{$size[1]} xc:none -fill white -draw \"roundRectangle 0,0 {$size[0]},{$size[1]} 15,15\" $image -compose SrcIn -gravity center -composite ";
// All on one line
$cmd = " -size {$width}x{$height} xc:none -fill red -draw \"roundRectangle 5,5 {$width},{$height} 20,20\" -compose dstout -matte miff:- ".
" ( -size {$size[0]}x{$size[1]} xc:none -fill white -draw \"roundRectangle 0,0 {$size[0]},{$size[1]} 15,15\" $image -compose SrcIn ) -gravity center -composite ";
echo "<pre>";
exec("convert $cmd rounded_corners4.png 2>&1", $array);
echo "<br>".print_r($array)."<br>";
echo "</pre>";
Image from this code:
Re: Rounded corner border on rounded corner image
Posted: 2010-06-10T11:30:45-07:00
by snibgo
A debug printing of $cmd might help.
The last "-composite" will have the previous "-compose" setting, which is "SrcIn", which might not be what you want. But the previous bracket has a "-compose" with no "-composite", which is suspicious.
$cmd seems to write to stdout and read from stdin. This is fine, but it looks as if you want the stdin to be read from the stdout, which won't work in a single command.
Re: Rounded corner border on rounded corner image
Posted: 2010-06-10T11:37:04-07:00
by Bonzo
This is what cmd =
Code: Select all
-size 646x340 xc:none -fill red -draw "roundRectangle 5,5 646,340 20,20" -compose dstout -matte miff:- ( -size 636x330 xc:none -fill white -draw "roundRectangle 0,0 636,330 15,15" small.jpg -compose SrcIn ) -gravity center -composite
Just noticed why I had a problem with and without the extra - as the | was missing. But still not working.
cmd =
Code: Select all
-size 646x340 xc:none -fill red -draw "roundRectangle 5,5 646,340 20,20" -compose dstout -matte miff:- | ( -size 636x330 xc:none -fill white -draw "roundRectangle 0,0 636,330 15,15" small.jpg -compose SrcIn ) -gravity center -composite over -
Re: Rounded corner border on rounded corner image
Posted: 2010-06-10T12:35:23-07:00
by snibgo
For "-composite over", you probably meant "-compose over -composite".
Here's a complete Windows script.
Code: Select all
rem Add a rounded corner by two different methods.
set SRC=logo:
set InRad=15
set OutRad=20
set BORDCOL=red
FOR /F "usebackq" %%L IN (`identify -format "WW=%%w\nHH=%%h" %SRC%`) DO set %%L
set /A wwOutRad=%WW%+OutRad
set /A hhOutRad=%HH%+OutRad
rem Method 1: three convert commands.
rem Create the red filled rounded rectangle
convert ^
-size %wwOutRad%x%hhOutRad% ^
xc:none ^
-fill %BORDCOL% -draw "roundRectangle 0,0 %wwOutRad%,%hhOutRad% %OutRad%,%OutRad%" ^
x.png
rem Create the image with the rounded rectangle
convert ^
-size %WW%x%HH% ^
xc:none ^
-fill white -draw "roundRectangle 0,0 %WW%,%HH% %InRad%,%InRad%" ^
%SRC% ^
-compose SrcIn -gravity center -composite ^
y.png
rem Combine the two
convert ^
x.png ^
y.png ^
-gravity center -compose Over -composite ^
border1.png
rem Method 2: Do it in one convert
convert ^
( ^
-size %wwOutRad%x%hhOutRad% ^
xc:none ^
-fill %BORDCOL% -draw "roundRectangle 0,0 %wwOutRad%,%hhOutRad% %OutRad%,%OutRad%" ^
) ^
( ^
-size %WW%x%HH% ^
xc:none ^
-fill white -draw "roundRectangle 0,0 %WW%,%HH% %InRad%,%InRad%" ^
%SRC% ^
-compose SrcIn -gravity center -composite ^
) ^
-gravity center -compose Over -composite ^
border2.png
Re: Rounded corner border on rounded corner image
Posted: 2010-06-10T12:58:57-07:00
by Bonzo
Strange my reply dissapered !
Thanks for your example snibgo I will take a look at it later.
I have found I can get the same incorrect
result without the miff:-
Code: Select all
$cmd = " -size {$width}x{$height} xc:none -fill red -draw \"roundRectangle 5,5 {$width},{$height} 20,20\" -compose dstout -matte ".
" ( -size {$size[0]}x{$size[1]} xc:none -fill white -draw \"roundRectangle 0,0 {$size[0]},{$size[1]} 15,15\" $image -compose SrcIn -matte ) -gravity center -compose over -composite ";
$cmd is now:
Code: Select all
-size 646x340 xc:none -fill red -draw "roundRectangle 5,5 646,340 20,20" -compose dstout -matte ( -size 636x330 xc:none -fill white -draw "roundRectangle 0,0 636,330 15,15" small.jpg -compose SrcIn -matte ) -gravity center -compose over -composite
Re: Rounded corner border on rounded corner image
Posted: 2010-06-10T13:25:10-07:00
by snibgo
So, your command is:
Code: Select all
convert
-size 646x340
xc:none -fill red -draw "roundRectangle 5,5 646,340 20,20"
-compose dstout -matte
( -size 636x330 xc:none -fill white -draw "roundRectangle 0,0 636,330 15,15"
small.jpg
-compose SrcIn -matte
)
-gravity center -compose over -composite
rounded_corners4.png
The first "-compose dstout -matte" is redundant. (It sets the compose method, but this setting is overwritten before it is used. "-matte" is implied by "xc:none".)
Likewise, -compose SrcIn -matte". But you need "-compose SrcIn -composite" here, to combine the rounded rectangle with small.jpg.
The only other difference to my version is the first roundRectangle. Your origin is "5,5" where mine is "0,0".
Re: Rounded corner border on rounded corner image
Posted: 2010-06-10T14:02:18-07:00
by Bonzo
Well done snibgo this works a treat:
Code: Select all
$cmd = " -size {$width}x{$height} xc:none -fill red -draw \"roundRectangle 0,0 {$width},{$height} 20,20\" ".
" ( -size {$size[0]}x{$size[1]} xc:none -fill white -draw \"roundRectangle 0,0 {$size[0]},{$size[1]} 15,15\" $image -compose SrcIn -composite ) -gravity center -compose over -composite ";
$cmd =
Code: Select all
-size 646x340 xc:none -fill red -draw "roundRectangle 0,0 646,340 20,20" ( -size 636x330 xc:none -fill white -draw "roundRectangle 0,0 636,330 15,15" small.jpg -compose SrcIn -composite ) -gravity center -compose over -composite
Re: Rounded corner border on rounded corner image
Posted: 2010-06-13T09:55:08-07:00
by Likao
im trying to do the same thing, but your code doesnt work for me, im using:
Code: Select all
-size 301x169 xc:none -fill red -draw "roundRectangle 0,0 301,169 20,20" ( -size 291x159 xc:none -fill white -draw "roundRectangle 0,0 291,159 15,15" images/VVD0900041-301-final.jpg -compose SrcIn -composite ) -gravity center -compose over -composite png:-
and i get "syntax error near unexpected token `(' "
Re: Rounded corner border on rounded corner image
Posted: 2010-06-13T10:31:07-07:00
by Likao
scratch that, all i needed was one more escape
Re: Rounded corner border on rounded corner image
Posted: 2010-06-13T13:23:02-07:00
by Bonzo
Sorry the code I posted was using XAMPP on Windows; on Linux you need to escape the ( & ) with a \